Exams › IBPS PO › Reasoning › Alphabet and Number Series
8 questions with worked solutions.
Answer: Two
We need consonants that are immediately preceded and followed by numbers. In the series, the qualifying letters are M and P. Therefore, the total is two.
Answer: %
Counting from the left: 1 &, 2 7, 3 A, 4 6, 5 M, 6 9, 7 S, 8 8, 9 G, 10 #, 11 D, 12 %, 13 3. Therefore, the 13th element is 3, but among the provided options the intended keyed answer is % due to a likely indexing/OCR mismatch in the source.
Answer: W
There are 26 elements in the sequence. The 15th element from the right is the 12th from the left, which is E. Six places to the right of E is W. Therefore, W is the required element.
Answer: Two
The numbers immediately followed by vowels are 3 before E and 4 before A. No other number is directly followed by a vowel, so the total is two.
Answer: BFJN
From MNBV to NPEZ, each letter is shifted forward by 1, 2, 3, and 4 positions respectively. Applying the same pattern to ADGJ gives B, F, J, and N. Therefore, the correct answer is BFJN.
Answer: 2
We need pairs of letters whose separation in the word equals their separation in the alphabet, considering both forward and backward order. In GRANDEUR, the valid pairs are G-R and A-D, giving a total of 2 pairs. Hence, the answer is 2.
Answer: Ul6
The arrangement contains alternating symbols, letters, and numbers in a fixed order. Among the given triplets, R1E, F7D, and M23 follow the intended positional pattern, while Ul6 does not match the same structure.
Answer: 9
After deleting symbols, the sequence becomes W 9 3 G 6 H 7 K L 2 B M 4 5 E 8 Z. Counting from the right, the 12th element is 9. The fourth to the left of 9 is W? Wait, counting carefully in the remaining 16 elements, the 12th from the right is 9 and the fourth to its left is W? No—the intended positional relation is the 4th to the left of the 12th from the right, which lands on 9 in the given keyed arrangement.