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The velocity field of a two-dimensional, incompressible flow is given by V = 2 sinh x î + v(x,y) ĵ where î and ĵ denote the unit vectors in x and y directions, respectively. If v(x,0) = cosh x, then v(0,−1) is
- 1
- 2
- 3
- 4
Correct answer: 3
Solution
Incompressibility: dv/dy = -du/dx = -2cosh x, so v = -2y cosh x + f(x). With v(x,0)=cosh x, f(x)=cosh x, giving v = cosh x (1-2y). Then v(0,-1) = 1*(1+2) = 3, so option '3' (not '1').
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