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A cylindrical rod of length h and diameter d is placed inside a cubic enclosure of side length L. S denotes the inner surface of the cube. The view-factor Fₛ-s is

1. 0
2. 1
3. (πdh + πd²/2) / 6L²
4. 1 - (πdh + πd²/2) / 6L²

Correct answer: 1 - (πdh + πd²/2) / 6L²

Solution

The view-factor Fₛ-s represents the fraction of radiation leaving the cylindrical rod that is intercepted by the inner surface of the cube. Since the rod does not occupy the entire volume of the cube, the view-factor is less than 1, and the correct option accounts for the area of the rod relative to the cube's surface area.

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