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For a simple compressible system, v, s, p and T are specific volume, specific entropy, pressure and temperature, respectively. As per Maxwell’s relations, (∂v/∂s) p is equal to

1. (∂s/∂T) p
2. (∂p/∂v) T
3. −(∂T/∂v) p
4. (∂T/∂p) s

Correct answer: (∂T/∂p) s

Solution

From the enthalpy potential dH=TdS+vdP, the Maxwell relation gives (dT/dp)_s=(dv/ds)_p. Therefore (dv/ds)_p equals (dT/dp)_s. The stored option is not a valid Maxwell pairing.

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