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Two electric charges q and −2q are placed at (0,0) and (6,0) on the x-y plane. The equation of the zero equipotential curve in the x-y plane is

1. x = −2
2. y = 2
3. x² + y² = 2
4. (x + 2)² + y² = 16

Correct answer: (x + 2)² + y² = 16

Solution

The zero equipotential curve represents points where the electric potential due to the two charges is zero. The correct option describes a circle centered at (-2, 0) with a radius of 4, which corresponds to the balance of potentials from the charges q and -2q, resulting in a net potential of zero at those points.

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