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In an 8085 microprocessor, the following program is executed Address location – Instruction 2000H XRA A 2001H MVI B,04H 2003H MVI A, 03H 2005H RAR 2006H DCR B 2007H JNZ 2005 200AH HLT At the end of program, register A contains

1. 60H
2. 30H
3. 06H
4. 03H

Correct answer: 60H

Solution

Starting with A=03H (00000011) and CY=0 after XRA A, four RAR (rotate-right-through-carry) operations give 03H->01H->80H->C0H->60H. Final A = 60H, not 30H.

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