Exams › GATE › Technical

A parallel plate capacitor consisting two dielectric materials is shown in the figure. The middle dielectric slab is placed symmetrically with respect to the plates. If the potential difference between one of the plates and the nearest surface of dielectric interface is 2 Volts, then the ratio ε1: ε2 is

1. 1:4
2. 2:3
3. 3:2
4. 4:1

Correct answer: 4:1

Solution

The ratio of the dielectric constants ε1 and ε2 is determined by the relationship between the electric field strengths in the two dielectrics, which is inversely proportional to their dielectric constants. Given that the potential difference across the dielectric interfaces is equal, the ratio of the distances and the potential differences leads to the conclusion that ε1: ε2 = 4:1.

Related GATE Technical questions

• C0 is the capacitance of a parallel plate capacitor with air as dielectric (as in figure (a)). If, half of the entire gap as shown in figure (b), is filled with a dielectric of permittivity εr, the expression for the modified capacitance is
• The undesirable property of an electrical insulating material is
• Q.17 In the formation of Routh-Hurwitz array for a polynomial, all the elements of a row have zero values. This premature termination of the array indicates the presence of
• Q.18 The root locus of a unity feedback system is shown in the figure
• Q.19 Power consumed by a balanced 3-phase, 3-wire load is measured by the two wattmeter method. The first wattmeter reads twice that of the second. Then the load impedance angle in radians is
• Q.20 In an oscilloscope screen, linear sweep is applied at the

⚔️ Practice GATE Technical free + battle 1v1 →