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A single-phase voltage-source inverter is controlled in single-pulse-width-modulated mode with a pulse width of 150° in each half-cycle. Total harmonic distortion is defined as \[ \mathrm{THD}=\sqrt{\frac{V_{\mathrm{rms}}^2-V_1^2}{V_1^2}}\times 100, \] where \(V_1\) is the rms value of the fundamental component of the output voltage. The THD of the output AC voltage waveform is:
- 65.65%
- 48.42%
- 31.83%
- 30.49%
Correct answer: 48.42%
Solution
In single-pulse PWM, the output waveform has a known Fourier series based on the pulse width. Using the rms value of the waveform and the rms value of the fundamental component, the THD evaluates to 48.42%.
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