Consider the following C program. #include struct Ournode{ char x,y,z; }; int main(){ struct Ournode p = {'1', '0', 'a'+2}; struct Ournode *q = &p; printf ("%c, %c", *((char*)q+1), *((char*)q+2)); return 0; } The output of this program is:

Question

Consider the following C program.

#include<stdio.h>
struct Ournode{
 char x,y,z;
};

int main(){
 struct Ournode p = {'1', '0', 'a'+2};
 struct Ournode *q = &p;
 printf ("%c, %c", *((char*)q+1), *((char*)q+2));
 return 0;
}

The output of this program is:

Accepted Answer

0,c. The program initializes a struct with characters, where '1' is at index 0, '0' at index 1, and 'a'+2 evaluates to 'c' at index 2. The pointer arithmetic used in the printf statement accesses the second and third characters of the struct, resulting in '0' and 'c' being printed.

Consider the following C program. #include<stdio.h> struct Ournode{ char x,y,z; }; int main(){ struct Ournode p = {'1', '0', 'a'+2}; struct Ournode q = &p; printf ("%c, %c", ((char)q+1), ((char*)q+2)); return 0; } The output of this program is:

Solution

Related GATE Technical questions

Consider the following C program. #include<stdio.h> struct Ournode{ char x,y,z; }; int main(){ struct Ournode p = {'1', '0', 'a'+2}; struct Ournode *q = &p; printf ("%c, %c", *((char*)q+1), *((char*)q+2)); return 0; } The output of this program is:

Solution

Related GATE Technical questions

Consider the following C program. #include<stdio.h> struct Ournode{ char x,y,z; }; int main(){ struct Ournode p = {'1', '0', 'a'+2}; struct Ournode q = &p; printf ("%c, %c", ((char)q+1), ((char*)q+2)); return 0; } The output of this program is: