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Consider the following pseudo code. What is the total number of multiplications to be performed? D = 2 for i = 1 to n do for j = i to n do for k = j + 1 to n do D = D * 3

1. Half of the product of the 3 consecutive integers.
2. One-third of the product of the 3 consecutive integers.
3. One-sixth of the product of the 3 consecutive integers.
4. None of the above.

Correct answer: One-sixth of the product of the 3 consecutive integers.

Solution

The correct option is right because the nested loops iterate in such a way that the total number of multiplications corresponds to the combination of choosing 3 distinct integers from a set of n, which mathematically is represented as n(n-1)(n-2)/6, equating to one-sixth of the product of three consecutive integers.

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