After applying the correction for elevation and temperature, the runway length is 700 m. The corrected runway length (in m) for an effective gradient of 1% is ______ (round off to the nearest integer).

Question

Accepted Answer

840. The corrected runway length accounts for the effective gradient, which increases the required length for safe takeoff and landing. A 1% gradient necessitates an increase in length to ensure performance standards are met, resulting in a total of 840 m.

After applying the correction for elevation and temperature, the runway length is 700 m. The corrected runway length (in m) for an effective gradient of 1% is ______ (round off to the nearest integer).

Solution

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