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A process equipment emits 5 kg/h of volatile organic compounds (VOCs). If a hood placed over the process equipment captures 95% of the VOCs, then the fugitive emission in kg/h is
- 0.25
- 4.75
- 2.50
- 0.48
Correct answer: 0.25
Solution
The hood captures 95% of the 5 kg/h of VOCs, which means it allows 5% to escape. Calculating 5% of 5 kg/h gives 0.25 kg/h as the fugitive emission.
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