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A flexible pavement has the following class of loads during a particular hour of the day:
i. 80 buses with 2-axles (each axle load of 40 kN)
ii. 160 trucks with 2-axles (front and rear axle loads of 40 kN and 80 kN, respectively)
The equivalent standard axle load repetitions for this vehicle combination as per IRC:37-2012 would be
- 180
- 240
- 250
- 320
Correct answer: 180
Solution
Standard axle = 80 kN, VDF = (P/80)^4. Buses: 80 x 2 axles of 40 kN = 160 x 0.0625 = 10. Trucks: 160 x [(40/80)^4 + (80/80)^4] = 160 x 1.0625 = 170. Total ESAL = 10 + 170 = 180.
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