On a section of a highway, the speed-density relationship is linear and is given by $v = 80 - \frac{2}{3}k$, where $v$ is in km/h and $k$ is in veh/km. The capacity of this section of the highway, in veh/h, is

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2400. Traffic flow is $q = vk = k\left(80-\frac{2}{3}k\right)$. This parabola attains maximum at $k = 60$ veh/km, giving $q_{max} = 60\times 40 = 2400$ veh/h. Hence the capacity is 2400 veh/h.

On a section of a highway, the speed-density relationship is linear and is given by \(v = 80 - \frac{2}{3}k\), where \(v\) is in km/h and \(k\) is in veh/km. The capacity of this section of the highway, in veh/h, is

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