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Denoting L as liquid and M as solid in a phase diagram, with subscripts representing different phases, a eutectoid reaction is described by

1. M_1 \rightarrow M_2 + M_3
2. L_1 \rightarrow M_1 + M_2
3. L_1 + M_1 \rightarrow M_2
4. M_1 + M_2 \rightarrow M_3

Correct answer: M_1 \rightarrow M_2 + M_3

Solution

A eutectoid reaction is a solid-state transformation in which one solid phase decomposes into two new solid phases. Therefore, the correct form is M_1 \rightarrow M_2 + M_3.

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