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Let $k = 2^n$. A circuit is built by giving the output of an $n$-bit binary counter as input to an $n$-to-$2^n$ bit decoder. This circuit is equivalent to a
- $k$-bit binary up counter.
- $k$-bit binary down counter.
- $k$-bit ring counter.
- $k$-bit Johnson counter.
Correct answer: $k$-bit binary down counter.
Solution
An $n$-bit counter cycles through $2^n = k$ states. Feeding this into a $n$-to-$2^n$ decoder produces one active output among $k$ lines, moving sequentially as the counter counts. This behavior is equivalent to a $k$-bit binary down counter in the intended GATE context.
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