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An unbalanced dice (with 6 faces, numbered from 1 to 6) is thrown. The probability that the face value is odd is 90% the probability that the face value is even. The probability of getting any even numbered face is the same.
If the probability that the face is even given that it is greater than 3 is 0.75, which one of the following options is closest to the probability that the face value exceeds 3 ?
- 0.453
- 0.468
- 0.485
- 0.492
Correct answer: 0.468
Solution
The correct option is derived from the relationship between the probabilities of odd and even outcomes, along with the conditional probability given that the outcome is greater than 3. By using the provided probabilities and the total probability theorem, we can calculate that the probability of rolling a number greater than 3 aligns closely with 0.468.
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