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A square pyramid has a base perimeter x, and the slant height is half of the perimeter. What is the lateral surface area of the pyramid?

1. x²
2. 0.75 x²
3. 0.50 x²
4. 0.25 x²

Correct answer: 0.25 x²

Solution

Base side = x/4 and slant height l = x/2. Lateral surface area = (1/2)*perimeter*slant = (1/2)*x*(x/2) = x^2/4 = 0.25 x^2. The stored 0.75 x^2 is wrong; correct is 0.25 x^2.

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