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The sum of the digits of a two digit number is 12. If the new number formed by reversing the digits is greater than the original number by 54, find the original number.

1. 39
2. 57
3. 66
4. 93

Correct answer: 39

Solution

With tens t and units u, t+u=12 and 9(u-t)=54 gives u-t=6, so u=9, t=3 and the original number is 39 (its reverse 93 is the larger one). The stored 93 is the reversed number, not the original.

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