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An ant walks in a straight line on a plane leaving behind a trace of its movement. The initial position of the ant is at point P facing east. The ant first turns 72° anticlockwise at P, and then does the following two steps in sequence exactly FIVE times before halting.
1. moves forward for 10 cm.
2. turns 144° clockwise.
The pattern made by the trace left behind by the ant is
- PQ = QR = RS = ST = TP = 10 cm
Correct answer: PQ = QR = RS = ST = TP = 10 cm
Solution
The ant consistently moves forward 10 cm after each turn, maintaining equal segment lengths, which results in a regular pattern. The combination of the 72° anticlockwise turn and the 144° clockwise turn creates a geometric shape where all sides are equal, confirming that each segment is indeed 10 cm.
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