Exams › GATE › General Aptitude
S, M, E, and F are working in shifts in a team to finish a project. M works with twice the efficiency of others but for half as many days as E worked. S and M have 6-hour shifts in a day, whereas E and F have 12-hour shifts. What is the ratio of contribution of M to contribution of E in the project?
- 1:1
- 1:2
- 1:4
- 2:1
Correct answer: 1:4
Solution
M works at twice the efficiency of E, but for half as many days, and also for 6 hours per day instead of E's 12 hours per day. So M's total contribution is multiplied by $2\times \frac{1}{2}\times \frac{6}{12}=\frac{1}{4}$ of E's contribution.
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