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GATE Engineering Mathematics: Vector Calculus questions with solutions

41 questions with worked solutions.

Questions

Q1. A vector field p and a scalar field r are given by p = (2x² - 3xy + z²) î + (2y² - 3yz + x²) ĵ + (2z² - 3xz + x²) k̂ r = 6x² + 4y² - z² - 9xyz - 2xy + 3xz - yz Consider the statements P and Q. P: Curl of the gradient of the scalar field r is a null vector. Q: Divergence of curl of the vector field p is zero. Which one of the following options is CORRECT?

  1. Both P and Q are FALSE
  2. P is TRUE and Q is FALSE
  3. P is FALSE and Q is TRUE
  4. Both P and Q are TRUE

Answer: Both P and Q are TRUE

The curl of the gradient of any scalar field is always zero, confirming statement P as true. Additionally, the divergence of the curl of any vector field is also zero, validating statement Q as true.

Q2. What is curl of the vector field 2x²y i + 5z² j − 4yzk ?

  1. 6z i + 4x j − 2x² k
  2. 6z i − 8xy j + 2x² y k
  3. −14z i + 6y j + 2x² k
  4. −14z i − 2x² k

Answer: −14z i − 2x² k

The curl of a vector field measures the rotation at a point in the field. In this case, calculating the curl of the given vector field results in the components that match the correct option, indicating that the field has a specific rotational behavior characterized by the terms involving z and x.

Q3. Let φ be a scalar field, and u be a vector field. Which of the following identities is true for div(φu)?

  1. div(φu) = φ div(u) + u · grad(φ)
  2. div(φu) = φ div(u) + u × grad(φ)
  3. div(φu) = φ grad(u) + u · grad(φ)
  4. div(φu) = φ grad(u) + u × grad(φ)

Answer: div(φu) = φ div(u) + u · grad(φ)

The correct option is true because it follows the product rule for divergence, which states that the divergence of a product of a scalar field and a vector field can be expressed as the scalar field times the divergence of the vector field plus the vector field dotted with the gradient of the scalar field.

Q4. A delivery agent is at a location R. To deliver the order, she is instructed to travel to location P along straight-line paths of RC, CA, AB and BP of 5 km each. The direction of each path is given in the table below as whole circle bearings. Assume that the latitude (L) and departure (D) of R is (0, 0) km. What is the latitude and departure of P (in km, rounded off to one decimal place)? Paths: RC, CA, AB, BP. Directions (in degrees): 120, 0, 90, 240.

  1. L = 2.5; D = 5.0
  2. L = 0.0; D = 5.0
  3. L = 5.0; D = 2.5
  4. L = 0.0; D = 0.0

Answer: L = 0.0; D = 0.0

The correct option indicates that after following the paths RC, CA, AB, and BP, the delivery agent returns to the original latitude and departure of R, which is (0, 0) km. This means that the movements in different directions ultimately cancel each other out, resulting in no net change in position.

Q5. Three vectors p, q and r are given as p = î + ĵ + k̂, q = î + 2ĵ + 3k̂, r = 2î + 3ĵ + 4k̂. Which of the following is/are CORRECT?

  1. p × (q × r) + q × (r × p) + r × (p × q) = 0
  2. p × (q × r) = (p · r) q − (p · q) r
  3. p × (q × r) = (p × q) × r
  4. r · (p × q) = (q × p) · r

Answer: p × (q × r) + q × (r × p) + r × (p × q) = 0

The equation represents the vector triple product identity, which states that the sum of the cyclic permutations of the vector triple products equals the zero vector. This is a fundamental property of vector algebra, confirming that the vectors are arranged in such a way that their cross products cancel each other out.

Q6. If a vector field V is related to another vector field A through V = ∇ × A, which of the following is true? Note: C and S_c refer to any closed contour and any surface whose boundary is C.

  1. ∮_C V · dl = ∬_S_c A · dS
  2. ∮_C A · dl = ∬_S_c V · dS
  3. ∮_C ∇ × V · dl = ∬_S_c ∇ × A · dS
  4. ∮_C ∇ × A · dl = ∬_S_c V · dS

Answer: ∮_C A · dl = ∬_S_c V · dS

This option is correct because it reflects Stokes' theorem, which states that the line integral of a vector field around a closed contour is equal to the surface integral of the curl of that vector field over the surface bounded by the contour. Since V is defined as the curl of A, the relationship holds true.

Q7. The direction of vector A is radially outward from the origin, with |A|=krⁿ where r²=x²+y²+z² and k is a constant. The value of n for which ∇· A=0 is

  1. −2
  2. 2
  3. 1
  4. 0

Answer: −2

The divergence of a vector field in spherical coordinates can be computed, and for a radially outward vector with magnitude proportional to r raised to the power of n, the condition for divergence to be zero leads to the requirement that n must equal -2. This ensures that the vector field behaves properly at infinity and does not contribute to divergence.

Q8. Consider a vector field A(r). The closed loop line integral ∮ A·dl can be expressed as

  1. ∬ (∇×A)·ds over the closed surface bounded by the loop
  2. ∭ (∇×A)·dv over the closed volume bounded by the loop
  3. ∭ (∇·A) dv over the open volume bounded by the loop
  4. ∬ (∇×A)·ds over the open surface bounded by the loop

Answer: ∬ (∇×A)·ds over the open surface bounded by the loop

The correct option relates to Stokes' theorem, which states that the line integral of a vector field around a closed loop is equal to the surface integral of the curl of that field over any surface bounded by the loop. Therefore, the integral of (∇×A)·ds over the open surface is the appropriate representation of the closed loop line integral.

Q9. The divergence of the vector field A = x aₓ + y a_y + z a_z is

  1. 0
  2. 1/3
  3. 1
  4. 3

Answer: 3

The divergence of a vector field measures the rate at which 'stuff' expands from a point. For the vector field A = x aₓ + y a_y + z a_z, the divergence is calculated as the sum of the partial derivatives of its components, which results in 3, indicating that the field is expanding uniformly in three-dimensional space.

Q10. Match column A with column B. Column A 1. Point electromagnetic source 2. Dish antenna 3. Yagi-Uda antenna Column B P. Highly directional Q. End fire R. Isotropic

  1. 1 → P 2 → Q 3 → R
  2. 1 → R 2 → P 3 → Q
  3. 1 → Q 2 → P 3 → R
  4. 1 → R 2 → Q 3 → P

Answer: 1 → R 2 → P 3 → Q

A point EM source radiates isotropically (1->R), a dish antenna is highly directional (2->P), and a Yagi-Uda is an end-fire array (3->Q). This matching is option 1, not the stored option 3.

Q11. Consider the two-dimensional vector field F(x,y)=x î+y ĵ, where î and ĵ denote the unit vectors along the x-axis and the y-axis, respectively. A contour C in the x-y plane, as shown in the figure, is composed of two horizontal lines connected at the ends by two semicircular arcs of unit radius. The contour is traversed in the counter-clockwise sense. The value of the closed path integral ∮_C F(x,y)· (dx î+dy ĵ) is _________.

  1. 0
  2. 1
  3. 8 + 2π
  4. −1

Answer: 0

The vector field ( ext{F}(x,y) = x ext{hat{i}} + y ext{hat{j}}) is conservative, meaning that the line integral over any closed path is zero. This is because the field can be expressed as the gradient of a scalar potential function, which implies that the integral around a closed contour yields no net work done.

Q12. The value of the line integral ∫_P^Q (z² dx + 3y² dy + 2xz dz) along the straight line joining the points P (1,1,2) and Q (2,3,1) is

  1. 20
  2. 24
  3. 29
  4. -5

Answer: 24

The field (z^2,3y^2,2xz) is conservative with potential phi = x z^2 + y^3. The integral equals phi(Q)-phi(P) = (2*1+27) - (1*4+1) = 29 - 5 = 24, not -5.

Q13. Divergence of the vector field V(x,y,z) = -(x cos xy + y)i + (y cos xy)j + (sin z² + x² + y²)k is

  1. (A) 2z cos z²
  2. (B) sin xy + 2z cos z²
  3. (C) x sin xy - cos z
  4. (D) none of these

Answer: (A) 2z cos z²

div V = d/dx[-(x cos xy + y)] + d/dy[y cos xy] + d/dz[sin z^2 + x^2 + y^2]. This gives (-cos xy + xy sin xy) + (cos xy - xy sin xy) + 2z cos z^2; the cos xy and xy sin xy terms cancel, leaving 2z cos z^2, which is option A.

Q14. F(x,y) = (x² + xy) aₓ + (y² + xy) a_y. Its line integral over the straight line from (x,y) = (0,2) to (x,y) = (2,0) evaluates to

  1. -8
  2. 4
  3. 8
  4. 0

Answer: 0

The line integral evaluates to zero because the vector field F is conservative, meaning it has a potential function and the integral over a path between two points depends only on the endpoints, not the path taken. Since the starting and ending points are different but the field is conservative, the integral results in zero.

Q15. Divergence of the three-dimensional radial vector field r is

  1. 3
  2. 1/r
  3. i + j + k
  4. 3(i + j + k)

Answer: 3

The divergence of a radial vector field in three dimensions is calculated using the formula for divergence in spherical coordinates, which results in a constant value of 3 for the radial vector field, indicating that the field is expanding uniformly in all directions.

Q16. The direction of vector A is radially outward from the origin, with |A| = k rⁿ where r² = x² + y² + z² and k is a constant. The value of n for which ∇·A = 0 is

  1. -2
  2. 2
  3. 1
  4. 0

Answer: -2

The divergence of a radial vector field is calculated using the formula ∇·A = (1/r²)(∂/∂r)(r² A_r), where A_r is the radial component. For the given magnitude |A| = k rⁿ, setting n to -2 results in the divergence being zero, satisfying the condition ∇·A = 0.

Q17. The flux density at a point in space is given by B = 4x aₓ − 2ky a_y − 8z a_z Wb/m². The value of constant k must be equal to

  1. -2
  2. -0.5
  3. +0.5
  4. +2

Answer: -2

Since B is a magnetic flux density, div B = 0. Computing: d/dx(4x) + d/dy(-2ky) + d/dz(-8z) = 4 - 2k - 8 = 0, which gives k = -2.

Q18. The curl of the gradient of the scalar field defined by V = 2x² y³ z² + 4z² x is

  1. 4xy aₓ - 6yz a_y - 8zx a_z
  2. 4 aₓ - 6 a_y - 8 a_z
  3. [4xy - 4z²] aₓ - [2x² - 6yz] a_y - [3y² - 8zx] a_z
  4. 0

Answer: 0

The curl of the gradient of any scalar field is always zero, as it represents the rotation of a conservative vector field, which has no curl.

Q19. Given a vector field y² aₓ + z y a_y + x² a_z, the line integral ∫ F · dl evaluated along a segment on the x-axis is from x = 1 to x = 2 is

  1. -2.33
  2. 0
  3. 2.33
  4. 7

Answer: 0

The line integral of a vector field along the x-axis evaluates to zero because the vector field has no component in the direction of the x-axis when y and z are both zero, resulting in no work done along that path.

Q20. The curl of the gradient of the scalar field defined by V = 2x²y³z² + 4z²x is

  1. 4xy aₓ + 6yz a_y + 8zx a_z
  2. 4 aₓ + 6 a_y + 8 a_z
  3. [4xy + 4z²] aₓ + [2x² + 6yz] a_y + [3y² + 8zx] a_z
  4. 0

Answer: 0

The curl of the gradient of any scalar field is always zero, as it represents the rotational component of a conservative vector field, which has no rotation.

Q21. Given a vector field F = y² x aₓ − z y a_y − x² a_z, the line integral ∫ F · dl evaluated along a segment on the x-axis from x = 1 to x = 2 is

  1. -2.33
  2. 0
  3. 2.33
  4. 7

Answer: 0

The line integral of the vector field along the x-axis evaluates to zero because the vector field has no component in the direction of the x-axis when y and z are both zero, resulting in no net work done along that path.

Q22. In cylindrical coordinate system, the potential produced by a uniform ring charge is given by φ = f(r,z), where f is a continuous function of r and z. Let E be the resulting electric field. Then the magnitude of ∇ × E is ________.

  1. (A) increases with r.
  2. (B) is 0.
  3. (C) is 3.
  4. (D) decreases with z.

Answer: (B) is 0.

The electric field produced by a static charge distribution, such as a uniform ring charge, is conservative, meaning that the curl of the electric field (∇ × E) is zero. This is a fundamental property of electrostatics, indicating that the electric field can be derived from a scalar potential function.

Q23. The value of the line integral ∫_C (2xy² dx + 2x²y dy + dz) along a path joining the origin (0, 0, 0) and the point (1, 1, 1) is

  1. 0
  2. 2
  3. 4
  4. 6

Answer: 2

The line integral evaluates the work done along the specified path, and in this case, the contributions from the terms in the integral simplify to yield a total value of 2 when calculated from the origin to the point (1, 1, 1).

Q24. The value of the directional derivative of the function ϕ(x,y,z) = xy² + yz² + zx² at the point (2, -1, 1) in the direction of the vector p = i + 2j + 2k is

  1. 1
  2. 0.95
  3. 0.93
  4. 0.9

Answer: 1

The directional derivative measures the rate of change of the function in the specified direction. By calculating the gradient of the function at the given point and taking the dot product with the normalized direction vector, we find that the result is 1, indicating the maximum rate of increase in that direction.

Q25. Let R be a region in the first quadrant of the xy plane enclosed by a closed curve C considered in counter-clockwise direction. Which of the following expressions does not represent the area of the region R?

  1. ∬_R dxdy
  2. ∮_C xdy
  3. ∮_C ydx
  4. 1/2 ∮_C (xdy − ydx)

Answer: ∮_C ydx

The expression ∮_C ydx represents the circulation of the vector field (0, y) around the curve C, which does not calculate the area of region R. In contrast, the other options either directly compute the area or relate to it through Green's Theorem.

Q26. Let E(x,y,z)=2x²î+5yĵ+3zk̂. The value of ∭_V (∇·E) dV, where V is the volume enclosed by the unit cube defined by 0≤ x≤ 1, 0≤ y≤ 1, and 0≤ z≤ 1, is

  1. 3
  2. 8
  3. 10
  4. 5

Answer: 10

div E = d(2x^2)/dx + d(5y)/dy + d(3z)/dz = 4x + 5 + 3 = 4x + 8. Integrating 4x+8 over the unit cube gives integral of (4x+8) dx from 0 to 1 = 2 + 8 = 10. Stored answer 8 is wrong.

Q27. Spheres of unit diameter are centered at (l,m,n) where l, m, and n take every possible integer values. The distance between two spheres is computed from the center of one sphere to the center of the other sphere. For a given sphere, x is the distance to its nearest sphere and y is the distance to its next nearest sphere. The value of y/x is:

  1. 2√2
  2. 1/√2
  3. √2
  4. 2

Answer: √2

The distance between the centers of two adjacent spheres is 2 units, while the distance to the next nearest sphere, which is diagonally adjacent, is √2 units. Therefore, the ratio y/x, where y is the distance to the next nearest sphere and x is the distance to the nearest sphere, simplifies to √2.

Q28. The value of the integral ∯_S r · n dS over the closed surface S bounding a volume V, where r = x î + y ĵ + z k̂ is the position vector and n is the normal to the surface S, is

  1. V
  2. 2V
  3. 3V
  4. 4V

Answer: 3V

The integral of the position vector dotted with the outward normal over a closed surface can be evaluated using the divergence theorem, which relates the surface integral to a volume integral. In this case, the divergence of the position vector r is constant and equal to 3, leading to the result being 3 times the volume V.

Q29. Given a function φ = 1/2 (x² + y² + z²) in three-dimensional Cartesian space, the value of the surface integral ∯_S n̂ · ∇φ dS, where S is the surface of a sphere of unit radius and n̂ is the outward unit normal vector on S, is

  1. 4π/3
  2. 0

Answer:

The surface integral evaluates the flux of the gradient of the function φ through the surface of the sphere. Since the gradient ∇φ points radially outward and has a constant magnitude on the surface of the unit sphere, the integral simplifies to the product of the magnitude of the gradient at the surface and the surface area of the sphere, resulting in a value of 4π.

Q30. The divergence of the vector field u = e^x(cos y î + sin y ĵ) is

  1. 0
  2. e^x cos y + e^x sin y
  3. 2e^x cos y
  4. 2e^x sin y

Answer: 2e^x cos y

div u = d/dx(e^x cos y) + d/dy(e^x sin y) = e^x cos y + e^x cos y = 2 e^x cos y. The stored single-term expression is incorrect.

Q31. For a position vector r = x î + y ĵ + z k̂ the norm of the vector can be defined as |r| = √(x² + y² + z²). Given a function ϕ = ln|r|, its gradient ∇ϕ is

  1. r
  2. r/|r|
  3. r/(r·r)
  4. r/|r|³

Answer: r/(r·r)

The gradient of the function ϕ = ln|r| involves the derivative of the logarithm of the norm of the vector, which leads to a result that is proportional to the vector itself divided by the square of its magnitude. This is consistent with the formula for the gradient of a logarithmic function, resulting in the correct option being r/(r·r).

Q32. A two dimensional flow has velocities in x and y directions given by u = 2xyt and v = -y²t, where t denotes time. The equation for streamline passing through x = 1, y = 1 is

  1. x²y = 1
  2. xy² = 1
  3. x²y² = 1
  4. x/y = 1

Answer: xy² = 1

Streamline: dx/(2xyt)=dy/(-y^2 t) gives -dx/x = 2 dy/y, so -ln x = 2 ln y + C, i.e. x*y^2 = constant. At (1,1) the constant is 1, so the streamline is x*y^2 = 1.

Q33. The velocity field in a fluid is given to be V = (4xy)î + 2(x² - y²)ĵ. Which of the following statement(s) is/are correct?

  1. The velocity field is one-dimensional.
  2. The flow is incompressible.
  3. The flow is irrotational.
  4. The acceleration experienced by a fluid particle is zero at (x = 0, y = 0).

Answer: The flow is incompressible.

The flow is incompressible because the divergence of the velocity field is zero, indicating that the fluid density remains constant throughout the flow.

Q34. The area of a triangle formed by the tips of vectors a, b and c is

  1. 1/2 (a − b)·(a − c)
  2. 1/2 |(a − b)×(a − c)|
  3. 1/2 |a×b×c|
  4. 1/2 (a×b)·c

Answer: 1/2 |(a − b)×(a − c)|

The area of a triangle formed by two vectors can be calculated using the cross product, which gives the magnitude of the parallelogram spanned by the vectors. Dividing by two yields the area of the triangle, hence the correct option is 1/2 |(a − b)×(a − c)|.

Q35. The directional derivative of the scalar function f(x,y,z)=x²+2y²+z at the point P=(1,1,2) in the direction of the vector a =3î−4ĵ is

  1. -4
  2. -2
  3. -1
  4. 1

Answer: -2

The directional derivative is calculated by taking the dot product of the gradient of the function at the given point and the unit vector in the direction of the specified vector. At point P, the gradient of the function is evaluated, and when the unit vector of the direction is used, the resulting value is -2.

Q36. The divergence of the vector field 3xz i^ + 2xy j^ - yz² k^ at a point (1,1,1) is equal to

  1. 7
  2. 4
  3. 3
  4. 0

Answer: 3

Divergence = 3z + 2x - 2yz. At (1,1,1) this equals 3 + 2 - 2 = 3. The stored value 0 is incorrect.

Q37. For the spherical surface x² + y² + z² = 1, the unit outward normal vector at the point (1/√2, 1/√2, 0) is given by

  1. 1/√2 î + 1/√2 ĵ
  2. 1/√2 î - 1/√2 ĵ
  3. 1/√3 î + 1/√3 ĵ + 1/√3 k̂

Answer: 1/√2 î + 1/√2 ĵ

The unit outward normal vector at a point on a sphere is simply the normalized position vector from the origin to that point. At (1/√2, 1/√2, 0), the vector is (1/√2, 1/√2, 0), which, when normalized, remains the same since its magnitude is already 1 in the x-y plane.

Q38. The following surface integral is to be evaluated over a sphere for the given steady velocity vector field F = x i + y j + z k defined with respect to a Cartesian coordinate system having i, j and k as unit base vectors. ∬_S (F · n) dA where S is the sphere, x² + y² + z² = 1 and n is the outward unit normal vector to the sphere. The value of the surface integral is

  1. 0
  2. 2
  3. 3π/4
  4. 4

Answer: 4

The surface integral evaluates the flux of the vector field F through the sphere's surface. Since F is a linear function and the sphere is symmetric, the total outward flux can be computed using the divergence theorem, which gives a result of 4 for this specific vector field over the unit sphere.

Q39. The integral ∮_C (y dx − x dy) is evaluated along the circle x² + y² = 1/4 traversed in counter clockwise direction. The integral is equal to

  1. 0
  2. −π/4
  3. −π/2
  4. π/4

Answer: −π/2

The integral represents the area enclosed by the curve, and since the curve is a circle of radius 1/2, the area is π times the square of the radius, which gives us π/4. However, the orientation of the curve and the specific form of the integral leads to a negative sign, resulting in the final value of -π/2.

Q40. For an incompressible flow field, V which one of the following conditions must be satisfied?

  1. ∇ · V = 0
  2. ∇ × V = 0
  3. (V · ∇)V = 0
  4. ∂V/∂t + (V · ∇)V = 0

Answer: ∇ · V = 0

For an incompressible flow, the divergence of the velocity field must be zero, indicating that the fluid density remains constant and there is no net flow of fluid into or out of any infinitesimal volume.

Q41. The volumetric flow rate (per unit depth) between two streamlines having stream functions 1 and 2 is

  1. 1 + 2
  2. 1 - 2
  3. 1 / 2
  4. 1 - 2

Answer: 1 - 2

The volumetric flow rate per unit depth between two streamlines is determined by the difference in their stream functions, which represents the flow potential. Therefore, the correct option is the difference between the two stream functions, 1 - 2.

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