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Common Data for Questions 48 and 49: The input voltage given to a converter is v_i = 100√(2) sin(100π t) V The current drawn by the converter is i_i = (10√(2) sin(100π t - π/3) + 5√(2) sin(300π t + π/4) + 2√(2) sin(500π t - π/6)) A Q.48 The input power factor of the converter is

1. 0.31
2. 0.44
3. 0.5
4. 0.71

Correct answer: 0.44

Solution

The input power factor is calculated by taking the ratio of the real power to the apparent power. In this case, the phase difference between the voltage and the fundamental component of the current leads to a power factor of 0.44, indicating that the converter is not operating at maximum efficiency.

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