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The voltage applied to a circuit is 100√2 cos(100πt) volts and the circuit draws a current of 10√2 sin(100πt + π/4) amperes. Taking the voltage as the reference phasor, the phasor representation of the current in amperes is

1. 10√2 ∠−π/4
2. 10∠−π/4
3. 10∠+π/4
4. 10√2 ∠+π/4

Correct answer: 10∠−π/4

Solution

The current is given in sine form, which can be converted to phasor form by recognizing that a sine function can be represented as a cosine function with a phase shift of -π/2. Thus, the current phasor becomes 10√2 at an angle of -π/4, but when expressed in standard phasor form, it simplifies to 10 at an angle of -π/4.

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