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Correct answer: $\frac{e^{-3s}}{s}(1-e^{-2s})$
The given signal is a rectangular pulse starting at $t=3$ and ending at $t=5$. Such a pulse can be written as $u(t-3)-u(t-5)$, whose Laplace transform is $\frac{e^{-3s}-e^{-5s}}{s} = \frac{e^{-3s}}{s}(1-e^{-2s})$.
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