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The area of the region bounded by the parabola y = x² + 1 and the straight line x + y = 3 is

1. 59/6
2. 9/2
3. 10/3
4. 7/6

Correct answer: 9/2

Solution

Intersections of y=x^2+1 and y=3-x: x^2+x-2=0 gives x=-2 and x=1. Area = integral from -2 to 1 of (2 - x - x^2) dx = 27/6 = 9/2. Stored answer 7/6 is wrong.

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