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Euclidean norm (length) of the vector [4 -2 -6]^T is
- √12
- √24
- √48
- √56
Correct answer: √56
Solution
The Euclidean norm is calculated as the square root of the sum of the squares of the vector's components. For the vector [4, -2, -6], this results in √(4² + (-2)² + (-6)²) = √(16 + 4 + 36) = √56.
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