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Consider a differentiable function \(f(x)\) on the set of real numbers such that \(f(-1)=0\) and \(|f'(x)|\le 2\). Which one of the following inequalities is necessarily true for all \(x\in[-2,2]\)?
- \(f(x)\le \frac{1}{2}|x+1|\)
- \(f(x)c2|x+1|\)
- \(f(x)c2\frac{1}{2}|x|\)
- \(f(x)c2|x|\)
Correct answer: \(f(x)c2|x+1|\)
Solution
By the Mean Value Theorem, \(|f(x)-f(-1)|\le 2|x-(-1)|=2|x+1|\). Since \(f(-1)=0\), this becomes \(|f(x)|\le 2|x+1|\). Among the given options, the intended correct inequality is \(f(x)\le 2|x+1|\).
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