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ExamsGATEEngineering Mathematics

With initial condition \(x(1)=0.5\), the solution of the differential equation \(t\,\dfrac{dx}{dt}+x=t\) is

  1. \(x=t-\tfrac12\)
  2. \(x=t^2-\tfrac12\)
  3. \(x=\tfrac{t^2}{2}\)
  4. \(x=\tfrac{t}{2}\)

Correct answer: \(x=\tfrac{t}{2}\)

Solution

The equation can be written as \(\dfrac{d}{dt}(tx)=t\). Integrating gives \(tx=t^2/2+C\), so \(x=t/2+C/t\). Using \(x(1)=0.5\) gives \(C=0\), hence \(x=t/2\).

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